any DTP operator (presentation operators) there working in UK?

Similar Threads:

1.AND OR operator won't work

With a mail merge I want to check if the fields "company" and "name" are
filled (not empty)if this is true then the text "attn. " has to be placed
before the name. Somehow it won't work, does anybody know why?

{COMPARE{MERGEFIELD company} <>""}

{COMPARE{MERGEFIELD name}<>""}

IF{=AND({COMPARE{MERGEFIELD company} <>""},{COMPARE{MERGEFIELD
name}<>""})}=1 "true" "false"}

Here the result of some fields:

0

1

false


1

1

false



The first two comparisions went well, the AND function doesn't seem to work,
whatever I change it remains "false", even if I replace AND with OR. Please
help.

2.Contact Searching - idiot operator

Outlook 2007.  I cannot for the life of me get search in contacts to turn up 
a thing.  Clearly I have some setting somewhere set to results=0 but I can't 
find it.

I have 847 items in Contacts.  I have 2 people named Alice.  I can see both 
entries on my main contacts screen.  Yet, when I plug in the word Alice in to 
'search all Contact Items',  I get the All Contact Items (Search Results) 
screen with a note that says 'No matches found for "alice".  Same results if 
I only plug in the letter 'a' - 'No matches found for "a".

This is driving me nuts.  

I have the same set of contacts on a different machine running Outlook 2003. 
 If I plug 'alice' into that search, I get the two Alices. So, while I'm an 
idiot, the condition apparently only started in 2007 :)

Where can I start to look for what's preventing the proper search results?

3.Ampersand operator in Header

I want to create an Excel yearly form with the only current year in the Header
Entering &d will give the current date but I only want the year. Entering 
&[YEAR] or &y doesn't work. This form is to be used on a club computer in 
which none of the members would be capable of creating a header by just going 
to View>Headers and Footers and have the Header display 'Annual Sale 2005'

4.Differential (upright "d") in Eqn Edtr is OPERATOR not function

5.[CZT-Devel] help with token's for operator word's

Hi Mike,

 XXXX@XXXXX.COM  wrote:
|>No "\dom" is just a NAME too.
| 
| The concrete parse tree of birthday book example in the standard maps
| \dom to PRE? 
| 
| What would happen if was declared it as a PRE and it did parse like the
| ISO example?
| 
| Would it cause any problems with other declarations?
|
\dom could be declared as PRE, but I think allowing function 
applications such as "Expression Expression" is good in Z, 
otherwise every time one wanted to declare a prefix function, they 
would have to declare an operator template for it, which would 
have an impact on a lot of existing Z specifications.

| In Fig1 it looks like \dom is performing an action on birthday which is
| how it should work.
| 
| The parsing would work like this:
| 
| (Going form bottom up)
| 
| 1) pass birthday into \dom
| 2) \dom will check if it's declaration can accept birthday's parameters 
|     see Fig1
|    \dom can accept a set that is a mapping of 2 parameters, see Fig3
| 	(\dom : (X \rel Y))
| 3)  Check to see if the passed set is also a mapping of 2 parameters,
| Fig2  
| 	(birthday: NAME \pfun DATE)	
| 4)  Yes it is
| 5)	Then make sure that what we return will also be a mapping, a
|       functional 	mapping of all the X, (\fun \power X)
|       That holds true for:
| 	\forall r : X \rel Y @ \dom r = \{~ p : r @ p.1 ~\}
| 
I'm not sure I follow this. Steps 2-5 seem like type inference to 
me, not parsing?

| Now going back to Fig1, Application contains a set who's constraints
| meat a condition that is working on a set called birthday, because
| application is the right side of the infix relational predicate "=" and
| the left side is DeclName (know) then point know to the set returned by
| Application.
|    
| If I call \dom NAME and birthday NAME I can't do the above?
| 
Hmm... I don't understand. Are you saying that you that the 
production "Expression = Expression Expression" (from the concrete 
syntax in section 8.2) cannot be parsed by a recursive decent parser?

Cheers,
Tim

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