any DTP operator (presentation operators) there working in UK?



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Re: any DTP operator (presentation operators) there working in UK?

Postby CyberTaz » Sat, 28 Apr 2007 19:55:55 GMT

1. Proper Grammar
2. Proper Spelling
3. Proper Punctuation
4. Proper Case Structure
5. Knowledge of page layout & Desktop Publishing software - which includes 
neither of the programs you cited.

If you acquire [some of] the above skills you should be well on your way! 
Unfortunately, this forum is not an employment agency.

Regards |:>)
Bob Jones
[MVP] Office:Mac

any DTP operator (presentation operators) there working in UK?

Postby RFRQIE9wZXJhdG9ycw » Sat, 28 Apr 2007 23:46:03 GMT

hi there! i am looking for a job in dtp (word, excel and powerpoint based 
jobs)?  if anyone working in similar job could pls tell me whats the area of 
expertise expected for this kinda job?

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Hi Mike,

|>No "\dom" is just a NAME too.
| The concrete parse tree of birthday book example in the standard maps
| \dom to PRE? 
| What would happen if was declared it as a PRE and it did parse like the
| ISO example?
| Would it cause any problems with other declarations?
\dom could be declared as PRE, but I think allowing function 
applications such as "Expression Expression" is good in Z, 
otherwise every time one wanted to declare a prefix function, they 
would have to declare an operator template for it, which would 
have an impact on a lot of existing Z specifications.

| In Fig1 it looks like \dom is performing an action on birthday which is
| how it should work.
| The parsing would work like this:
| (Going form bottom up)
| 1) pass birthday into \dom
| 2) \dom will check if it's declaration can accept birthday's parameters 
|     see Fig1
|    \dom can accept a set that is a mapping of 2 parameters, see Fig3
| 	(\dom : (X \rel Y))
| 3)  Check to see if the passed set is also a mapping of 2 parameters,
| Fig2  
| 	(birthday: NAME \pfun DATE)	
| 4)  Yes it is
| 5)	Then make sure that what we return will also be a mapping, a
|       functional 	mapping of all the X, (\fun \power X)
|       That holds true for:
| 	\forall r : X \rel Y @ \dom r = \{~ p : r @ p.1 ~\}
I'm not sure I follow this. Steps 2-5 seem like type inference to 
me, not parsing?

| Now going back to Fig1, Application contains a set who's constraints
| meat a condition that is working on a set called birthday, because
| application is the right side of the infix relational predicate "=" and
| the left side is DeclName (know) then point know to the set returned by
| Application.
| If I call \dom NAME and birthday NAME I can't do the above?
Hmm... I don't understand. Are you saying that you that the 
production "Expression = Expression Expression" (from the concrete 
syntax in section 8.2) cannot be parsed by a recursive decent parser?


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