Need ANSI 837 control

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  • 1. Clarion and Muilt WAN Sites
    Cgroup, What is the best data source to use in a WAN situation using an ABC/IDE app. Is TPS - Too Slow over WAN ? Best Regards Rob c5.5h c6.0
  • 2. ARRAY EXPERT NEEDED
    Hi All Does anyone know how to lookat array elements in an array in one statement. e.g. look at Myarray [1,1] to Myarray[2,20] and sum the contents of each element.Each element in the array has two conditions 0 or 1 so in the above two dimension array 20 x 20 elements if each element is 1 the result would be 40 and if 20 elements were 0 the result would be 20. Help appreciated. Eddie

Need ANSI 837 control

Postby Robert Johnson » Sat, 01 Nov 2003 04:03:52 GMT

Hi all.  I am looking for a template or control to do ANSI 837 electronic
claims for Medicare.  Does anyone have one or know of one?  I had
communicated with Jim Highsmith at caresel.com last year but he has
disappeared and the web site is down.  I need a solution ASAP.

Regards,

Robert



Re: Need ANSI 837 control

Postby r jolda » Sat, 01 Nov 2003 11:20:48 GMT

Hi Robert,
We have an 837 solution.  I'll E Mail you privately.
Ron Jolda,
PDMG











Re: Need ANSI 837 control

Postby SYNCHSYS » Mon, 03 Nov 2003 10:30:13 GMT

Ron,

Please send me information as well.

Thanks

Peter Rabolt
Synchronized Systems Inc
 XXXX@XXXXX.COM 








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1.Build your own Forth for Microchip PIC (Episode 837)

2.ANSI escape control codes for the Forth console

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3.Harbour ANSI C sprintf() for ANSI SQL.

This is a multi-part message in MIME format.
IMHO.-
I need to implement a sprintf () compatible ANSI C and ANSI SQL to generate HTML, mount SQL sentences of an effective way in
critical processes or simply mount messages of the application and debugging of a easy way.

Attach spd.c file, please check if it is Harbour compatible.
For my part is no objection to incorporate in the project if you consider it opportune.

----------------------------------
Tengo necesidad de implementar un sprintf() compatible ANSI C y ANSI SQL para poder generar HTML, montar sentencias SQL de una
forma efectiva en procesos cricos o sencillamente, montar mensajes de la aplicaci y de depuraci de una forma m simple.

Adjunto el fichero spd.c, por favor, chequear si es Harbour compatible.
Por mi parte no hay ning inconveniente en que se incorpore al proyecto si lo considers oportuno.
----------------------------------

Procedure Test()
        Local i, n, k, nCount := 0, nMaxCount := 100000
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        nCount := 17/13
        cRes := _SPD( "%%%-3.2f%%%n SQL DATE %s%n SQL %s SQL %d SQL %s%n", ;
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        ? cRes   // "%1.31% SQL DATE 2008-05-18 SQL TRUE SQL 0 SQL NULL"
        ? i, n, k	// 6 26 50

        cSQL := "SELECT * FROM Tabla WHERE Fecha >= '%s' AND Fecha < '%s'"
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        for i := 1 to nMaxCount
           cRes := _SPD( cSQL, dFecha1, dFecha2 )
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best regards
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5.Need help understanding program control/flow.

Hi all! Newbie here.

Below is an example from Teach Yourself C in 21 Days. My apologies
if it is a bit long.

What I don't understand is how the "get_data" function can call the
"continue_function", and if NO is returned to "get_data", display_report
executes and the program ends? Basically I am having trouble understanding
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The "if" loops only initiates if cont=YES, so what happens if a function
in the loop(in this case get_data) gets cont=NO? Does this really mean
that if "something" within an "if" loop doesn't meet the condition of the  
loop,
the result is that the next statement below the "something" gets executed
and the the "if" loop is exited?

Hope I made myself clear.

Thanks in advance!

===============================================================================
#include <stdio.h>

#define MAX   100
#define YES   1
#define NO    0

/*--------------------*/
/* variables          */
/*--------------------*/

long   income[MAX]; /* to hold incomes     */
int    month[MAX], day[MAX], year[MAX]; /* to hold birthdays */
int     x, y, ctr;   /* For counters        */
int     cont;  /* For program control */
long    month_total, grand_total;  /* For totals      */

/*--------------------*/
/* function prototypes*/
/*--------------------*/

int main(void);
int display_instructions(void);
void get_data(void);
void display_report(void);
int continue_function(void);

/*--------------------*/
/* start of program   */
/*--------------------*/

int main(void)
{
     cont = display_instructions();

     if ( cont == YES )     /* <================================ LOOK HERE!  
*/
     {
         get_data();
         display_report();
     }
     else
         printf( "\nProgram Aborted by User!\n\n");

    return 0;
}
/*-----------------------------------------------------------*
  *  Function:  display_instructions()                        *
  *  Purpose:   This function displays information on how to  *
  *             use this program and asks the user to enter 0 *
  *             to quit, or 1 to continue.                    *
  *  Returns:   NO  - if user enters 0                        *
  *             YES - if user enters any number other than 0  *
  *-----------------------------------------------------------*/
int display_instructions( void )
{
    printf("\n\n");
    printf("\nThis program enables you to enter up to 99 people\'s ");
    printf("\nincomes and birthdays.  It then prints the incomes by");
    printf("\nmonth along with the overall income and overall average.");
    printf("\n");

    cont = continue_function();
    return( cont );
}
/*-------------------------------------------------------------*
  *  Function:  get_data() *
  *  Purpose: This function gets the data from the user. It     *
  *           continues to get data until either 100 people are *
  *           entered, or until the user enters 0 for the month.*
  *  Returns: nothing *
  *  Notes:   This allows 0/0/0 to be entered for birthdays in  *
  *           case the user is unsure.  It also allows for 31   *
  *           days in each month.                               *
  *-------------------------------------------------------------*/

void get_data(void)
{
    for ( cont = YES, ctr = 0; ctr < MAX && cont == YES; ctr++ )
    {
       printf("\nEnter information for Person %d.", ctr+1 );
       printf("\n\tEnter Birthday:");

       do
       {
           printf("\n\tMonth (0 - 12): ");
           scanf("%d", &month[ctr]);
       }while (month[ctr] < 0 || month[ctr] > 12 );

       do
       {
           printf("\n\tDay (0 - 31): ");
           scanf("%d", &day[ctr]);
       }while ( day[ctr] <  0 || day[ctr] > 31 );

       do
       {
           printf("\n\tYear (0 - 2002): ");
           scanf("%d", &year[ctr]);
       }while ( year[ctr] < 0 || year[ctr] > 2002 );

       printf("\nEnter Yearly Income (whole dollars): ");
       scanf("%ld", &income[ctr]);

       cont = continue_function();  /*  
<===================================== LOOK HERE! */
    }
    /* ctr equals the number of people that were entered.    */
}
/*----------------------------------------------------------*
  *  Function: display_report()                              *
  *  Purpose:  This function displays a report to the screen *
  *  Returns:  nothing                                       *
  *  Notes:    More information could be printed.            *
  *----------------------------------------------------------*/

void display_report()
{
     grand_total = 0;
     printf("\n\n\n");                   /* skip a few lines   */
     printf("\n        SALARY SUMMARY");
     printf("\n        ==============");

     for( x = 0; x <= 12; x++ )  /* for each month, including 0*/
     {
        month_total = 0;
        for( y = 0; y < ctr; y++ )
        {
            if( month[y] == x )
                month_total += income[y];
        }
        printf("\nTotal for month %d is %ld", x, month_total);
        grand_total += month_total;
     }
     printf("\n\nReport totals:");
     printf("\nTotal Income is %ld", grand_total);
     printf("\nAverage Income is %ld", grand_total/ctr );

     printf("\n\n* * * End of Report * * *\n");
}
/*----------------------------------------------------------------*
  * Function: continue_function()                                  *
  * Purpose:  This function asks the user if they wish to continue.*
  * Returns:  YES - if user wishes to continue                     *
  *           NO - if user wishes to quit                          *
  *----------------------------------------------------------------*/

int continue_function( void )
{
     printf("\n\nDo you wish to continue? (0=NO/1=YES): ");
     scanf( "%d", &x );

     while( x < 0 || x > 1 )
     {
         printf("\n%d is invalid!", x);
         printf("\nPlease enter 0 to Quit or 1 to Continue: ");
         scanf("%d", &x);
     }
     if(x == 0)
         return(NO);
     else
         return(YES);
}
==================================================================================

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