Can't get the xaxis to cross at value 0 for both yaxes
by RGVyZWs » Wed, 19 Mar 2008 04:05:01 GMT
Hello 
I am working on an Excel chart with both a primary and secondary yaxis and
only one xaxis. The primary has positive and negative values. The
secondary has all positive values. I am using the secondary as a rank (by
selecting the box to invert values so the highest rank has a value of 1 and
appears at the top of the secondary yaxis, where rank 25 is the lowest
possible rank and appears at the bottom of the secondary yaxis), in theory
where the x and y axes meet. The xaxis is different points in time. So
this chart shows trends over time.
The issue I am having is the primary xaxis crosses the primary yaxis at 0
(yaxis value), which is what I want. However, the primary xaxis crosses
the secondary yaxis at a value that is not the lowest value on the secondary
yaxis. In this case, since I am using it as a rank, it is not crossing at
the lowest rank. I am not showing the secondary xaxis associated with rank.
I don't have this issue if all of the values on the primary yaxis are
positive. In other words, the primary xaxis crosses at 0 on the primary
yaxis and at the lowest rank on the secondary axis.
My question is, is there a way to fix my problem? Is there an option where
I can set the value where the primary xaxis crosses a value on the secondary
yaxis? I know I can set the value for Primary xaxis to primary yaxis 
and do the same for the secondary x and y axes, but I'm not aware of a way to
cross this primary  secondary boundary.
I imagine the graph's axes looking like a backwards 4  the primary yaxis
goes above and below the primary xaxis. The primary xaxis is approximately
in the middle. The secondary yaxis is as high as the primary yaxis but
only goes down to the xaxis (i.e., it does not extend below the xaxis). Is
this possible?
Something like this:
 
_______


Thanks!
 Derek
Re: Can't get the xaxis to cross at value 0 for both yaxes
by Jon Peltier » Wed, 19 Mar 2008 04:39:41 GMT
You have to fix the secondary axis so it goes as far negative as a
proportion of its full scale as the primary axis does. You can do it
manually or using a VBA procedure:
http://www.******.com/
 Jon

Jon Peltier, Microsoft Excel MVP
Tutorials and Custom Solutions
Peltier Technical Services, Inc.  http://www.******.com/
_______
Re: Can't get the xaxis to cross at value 0 for both yaxes
by RGVyZWs » Wed, 19 Mar 2008 05:34:02 GMT
i Jon 
Thanks for the quick response.
I understand what you are saying in terms of having the primary and
secondary yaxes in proportion to each other, but I think the wrinkle in my
chart is I am using the secondary yaxis as a rank with the lowest rank at
the bottom where the yaxis meets the xaxis.
I completely agree with your suggestion if I were dealing with numbers going
in the same direction on both yaxes, but that is not the case here, since
you can't have a negative rank and I have rank in descending order with $
values in ascending order.
So my envisioned chart looks like this with $ as a bar graph (primary axis)
and rank as a line graph (secondary axis). I want the secondary yaxis to
cross / stop at the primary xaxis at xaxis value $0. If I have the rank
proportions to the $ amounts, it implies a $0 is not the bottom rank, which
is not always the case in my data set. I don't want the primary xaxis to
imply $0 is not ranked the lowest.
$100   Rank 1
 
 
$0 _________Rank 25


($100)
Q1 Q2 Q3
 Derek

"Jon Peltier" wrote:
Re: Can't get the xaxis to cross at value 0 for both yaxes
by Jon Peltier » Wed, 19 Mar 2008 06:20:14 GMT
didn't say plot numbers along the negative secondary Y axis, I was telling
you how to align the 0 point of each Y axis. If you don't want the negative
part of the axis to show, don't display any part of the axis (format: no
line), and add an XY series to the chart to serve as a fake axis:
http://peltiertech.com/Excel/Charts/ArbitraryAxis.html
 Jon

Jon Peltier, Microsoft Excel MVP
Tutorials and Custom Solutions
Peltier Technical Services, Inc.  http://PeltierTech.com
_______
"Derek" < XXXX@XXXXX.COM > wrote in message
news: XXXX@XXXXX.COM ...
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