Newbie question: Small blocks

Similar Threads:

1.newbie question about blocks

Hi, I want to square every element in my array using a block:

a = (1..1000).to_a
a.each {|x| x**2}

But this does not seem to work, it just outputs my array completely
unchanged :(

--
"winners never quit, quitters never win"

2.Newbie Question: Blocks and Parameters

3.Newbie question re. blocks & variable scope

Hi,

I'd like to ask for some help with local variable scope.  I understand
that the scope of a local variable is the "do...end" block in which it
is created.  However, the code below shows that the value assigned to
the variable within a block does not persist after the single
iteration in which the variable is given that value, although the
variable is still defined in a later iteration. That is, in the idx=2
iteration, Ruby does not remember that a=11 in the previous iteration,
but it also does not complain about an undefined local variable "a"
(which it of course does outside the block). I haven't been able to
find this behavior mentioned in the documentation or in this
group--can you point me to something that will clarify for me what is
going on?

Thanks,
Steve

data=[1,2]
data.each do | idx|
	if idx == 1
		a = 11
		print "idx=1: a=",a,"\n"
	elsif idx == 2
		b = 12
		print "idx=2: a=",a," b=",b,"\n"
	end
end
print "after:\n"
print "a=",a," b=",b,"\n"
	
>c:\ruby\bin\ruby test.rb
idx=1: a=11
idx=2: a=nil b=12
after:
test.rb:12: undefined local variable or method `a' for main:Object
(NameError)
>Exit code: 1

4.Newbie block question

Hi folks

I'm working on some code that extracts data from a set of XML files 
using REXML stores this as arrays of arrays of floats (one array of 
floats per file), does some processing and then writes the results to 4 
text files for visualisation with gnuplot.

However, what happens is that although 4 files get created all the data 
gets saved in the first one to be opened. It's as if the block in 
writeMatrix() stores the reference to the first File object and uses 
that on the other 3 method invocations. If that's the case then I've 
obviously failed to understand the appropriate way to use a block.

What would be a better way to code this in ruby?

thanks

Dave

Here's a portion of the class handling writing the files.

class TuneInputData

   ... snip snip ...

  def writeData()

    writeMatrix(@@LUMINANCE_DATA_FILE, @imageVector)

    writeMatrix(@@VOICE_DATA_FILE, @voiceVector)

    writeMatrix(@@SOUND_DATA_FILE, @soundVector)

    writeMatrix(@@RHYTHM_DATA_FILE, @rhythmVector)

    writeColumn(@@COLOURFULNESS_DATA_FILE, @imageColourfulness)

  end

  def writeMatrix(filename, matrix)

    file = File.new(filename, "w")

    matrix.each { |row| writeRow(file, row) }

  end

  def writeRow(file, row) 

    outString = ""

    row.each { |v| outString = outString + v.to_s + " " }

    file.puts(outString)

  end

  ... snip snip ...

end

5.procs/blocks - blocks with procs, blocks with blocks?

Well, maybe not blocks with blocks but blocks with yield?  although
right now, I only have a fix for procs with blocks and not blocks with
blocks via blocks with yield when a proc block is not in stock...

class Proc
  alias __proc_block_call call
  alias __proc_block_indexer []
  
  def call(*args, &block)
    __proc_block_call(*(block.nil? ? args : args << block))
  end
  
  def [](*args, &block)
    __proc_block_indexer(*(block.nil? ? args : args << block))
  end
end

-----
usage

prc = Proc.new {|arg, proc_block|
  p arg
  proc_block[arg]
}

prc.call("Foo") {|*what|
  puts "Got #{what.length} whats -- #{what.inspect}"
}

produces:

"Foo"
Got 1 whats -- ["Foo"]


- also - it looks like the indexer function cannot take a block (parse
error) - why?

6. Small regexp question

7. small question about ruby -c

8. small array/hash question