using pipe in shell script

Dear all,

I found I cannot use a variable name as the input of the command "cat" 
followed by piping the result. Could any body tell me how to solve the 
problem?

cat $filename |\
        while read line
        do
        echo "$line read from $filename"
        done

Try:
while read line
do
   echo "$line read from $filename"
done < $filename

	Cheers,
		Gary	B-)

And what's the problem? Your code works just fine (with bash).
What does not work for you?

--($:~)-- cat $filename | while read line ; do echo "$line read from $filename" ; done
:set hlsearch read from .vimrc
--($:~)-- echo $filename
.vimrc

BTW: That was UUOC. Better to do:

while read line; do echo "$line read from $filename"; done < $filename

Michael

Gary's solution is good for this specific problem.  In the more general
case, where there's no alternative to piping stdout into a loop, 
you'll avoid this problem by using ksh and not bash.


-- 
             Christopher Mattern

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What problem? The code that's been posted by the OP works



But you're right though, Garys solution is better than the one
posted by the OP, as it avoids a UUOC.

Anyway - I'd *really* be interested in knowing the problem you talk
about.

Michael Schmarck
-- 
"You're just the sort of person I imagined marrying, when I was little...
except, y'know, not green... and without all the patches of fungus."
                -- Swamp Thing